区域定位java代码实现 区域定位java代码实现方法
java简单定位及位子确定的代码具体看补充
(3,4,N)
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上北下南左西又东
顺时针排序：北东南西
北1 东2 南3 西4
（3,4,1）
左转1+1=2东
右转1-1=01,则0=4西
后转1+2=3南
可以把朝向问题看成类似约瑟夫的问题。
用数组记录当前坐标X Y 及朝向。用1,2,3,4代表北东南西
左转后，（3,4,2）
往前一步，
当朝向不同的时候，有对应的向前向后是改变哪个坐标值，
写四个朝向时候的坐标的算法
然后调用，传入2，则调用case=2时的动作，如果向前则~~~向后则~~~~再命令转向则（调用处理方向改变的函数）~~~~
最后输出（，，），对最后一个兑换成“东南西北”输出就行了
()
java如何实现电子地图的定位
CellInfoManager
import java.lang.reflect.Method;
import java.util.Iterator;
import java.util.List;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.content.Context;
import android.telephony.CellLocation;
import android.telephony.NeighboringCellInfo;
import android.telephony.PhoneStateListener;
import android.telephony.TelephonyManager;
import android.telephony.gsm.GsmCellLocation;
import android.util.Log;
public class CellInfoManager {
private int asu;
private int bid;
private int cid;
private boolean isCdma;
private boolean isGsm;
private int lac;
private int lat;
private final PhoneStateListener listener;
private int lng;
private int mcc;
private int mnc;
private int nid;
private int sid;
private TelephonyManager tel;
private boolean valid;
private Context context;
public CellInfoManager(Context paramContext) {
this.listener = new CellInfoListener(this);
tel = (TelephonyManager) paramContext.getSystemService(Context.TELEPHONY_SERVICE);
this.tel.listen(this.listener, PhoneStateListener.LISTEN_CELL_LOCATION | PhoneStateListener.LISTEN_SIGNAL_STRENGTH);
context = paramContext;
}
public static int dBm(int i) {
int j;
if (i = 0 i = 31)
j = i * 2 + -113;
else
j = 0;
return j;
}
public int asu() {
return this.asu;
}
public int bid() {
if (!this.valid)
update();
return this.bid;
}
public JSONObject cdmaInfo() {
if (!isCdma()) {
return null;
}
JSONObject jsonObject = new JSONObject();
try {
jsonObject.put("bid", bid());
jsonObject.put("sid", sid());
jsonObject.put("nid", nid());
jsonObject.put("lat", lat());
jsonObject.put("lng", lng());
} catch (JSONException ex) {
jsonObject = null;
Log.e("CellInfoManager", ex.getMessage());
}
return jsonObject;
}
public JSONArray cellTowers() {
JSONArray jsonarray = new JSONArray();
int lat;
int mcc;
int mnc;
int aryCell[] = dumpCells();
lat = lac();
mcc = mcc();
mnc = mnc();
if (aryCell == null || aryCell.length 2) {
aryCell = new int[2];
aryCell[0] = cid;
aryCell[1] = -60;
}
for (int i = 0; i aryCell.length; i += 2) {
try {
int j2 = dBm(i + 1);
JSONObject jsonobject = new JSONObject();
jsonobject.put("cell_id", aryCell[i]);
jsonobject.put("location_area_code", lat);
jsonobject.put("mobile_country_code", mcc);
jsonobject.put("mobile_network_code", mnc);
jsonobject.put("signal_strength", j2);
jsonobject.put("age", 0);
jsonarray.put(jsonobject);
} catch (Exception ex) {
ex.printStackTrace();
Log.e("CellInfoManager", ex.getMessage());
}
}
if (isCdma())
jsonarray = new JSONArray();
return jsonarray;
}
public int cid() {
if (!this.valid)
update();
return this.cid;
}
public int[] dumpCells() {
int[] aryCells;
if (cid() == 0) {
aryCells = new int[0];
return aryCells;
}
ListNeighboringCellInfo lsCellInfo = this.tel.getNeighboringCellInfo();
if (lsCellInfo == null || lsCellInfo.size() == 0) {
aryCells = new int[1];
int i = cid();
aryCells[0] = i;
检举补充回答：
return aryCells;
}
int[] arrayOfInt1 = new int[lsCellInfo.size() * 2 + 2];
int j = 0 + 1;
int k = cid();
arrayOfInt1[0] = k;
int m = j + 1;
int n = asu();
arrayOfInt1[j] = n;
IteratorNeighboringCellInfo iter = lsCellInfo.iterator();
while (true) {
if (!iter.hasNext()) {
break;
}
NeighboringCellInfo localNeighboringCellInfo = (NeighboringCellInfo) iter.next();
int i2 = localNeighboringCellInfo.getCid();
if ((i2 = 0) || (i2 == 65535))
continue;
int i3 = m + 1;
arrayOfInt1[m] = i2;
m = i3 + 1;
int i4 = localNeighboringCellInfo.getRssi();
arrayOfInt1[i3] = i4;
}
int[] arrayOfInt2 = new int[m];
System.arraycopy(arrayOfInt1, 0, arrayOfInt2, 0, m);
aryCells = arrayOfInt2;
return aryCells;
}
public JSONObject gsmInfo() {
if (!isGsm()) {
return null;
}
JSONObject localObject = null;
while (true) {
try {
检举补充回答： JSONObject localJSONObject1 = new JSONObject();
String str1 = this.tel.getNetworkOperatorName();
localJSONObject1.put("operator", str1);
String str2 = this.tel.getNetworkOperator();
if ((str2.length() == 5) || (str2.length() == 6)) {
String str3 = str2.substring(0, 3);
String str4 = str2.substring(3, str2.length());
localJSONObject1.put("mcc", str3);
localJSONObject1.put("mnc", str4);
}
localJSONObject1.put("lac", lac());
int[] arrayOfInt = dumpCells();
JSONArray localJSONArray1 = new JSONArray();
int k = 0;
int m = arrayOfInt.length / 2;
while (true) {
if (k = m) {
localJSONObject1.put("cells", localJSONArray1);
localObject = localJSONObject1;
break;
}
int n = k * 2;
int i1 = arrayOfInt[n];
int i2 = k * 2 + 1;
int i3 = arrayOfInt[i2];
JSONObject localJSONObject7 = new JSONObject();
localJSONObject7.put("cid", i1);
localJSONObject7.put("asu", i3);
localJSONArray1.put(localJSONObject7);
k += 1;
}
} catch (JSONException localJSONException) {
localObject = null;
}
}
}
public boolean isCdma() {
if (!this.valid)
update();
如何用java实现“通过根据给定的经纬度生成区域”？
使用第三方jar包 jts包 例子如下面 \x0d\x0a\x0d\x0a//一个面所包含的经纬度（标准的经纬*3600000） \x0d\x0aString str = "POLYGON ((419164412 143703543, 419164481 143702737, 419164494 143702527,419164412 143703543))"; \x0d\x0aWKTReader wkt = new WKTReader(); \x0d\x0aGeometry geojudge1 = wkt.read(str); \x0d\x0aint xpoi = 419164481; \x0d\x0aint ypoi = 143702737; \x0d\x0aGeometry geojudge2 = wkt.read("POINT(" + xpoi + " " + ypoi + "))"); \x0d\x0a\x0d\x0aif(geojudge1.intersects(geojudge2)) { \x0d\x0aSystem.out.println("xpoi、ypoi 在这个面里"); \x0d\x0a} \x0d\x0a\x0d\x0aps:在构成一个面的时候，第一个点的经纬度一定要与最后一个点的经纬度相同。否则会报错误：java.lang.IllegalArgumentException: points must form a closed linestring
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