关于vb.net鼠标释放的信息
VB.net怎样按住鼠标移动无边框窗体
1.在mouse事件中实现
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2.调用windows API
实现方式为：
1.在mouse事件中实现
[csharp] view plain copy
Point mouseOff;//鼠标移动位置变量
bool leftFlag;//标签是否为左键
private void groupControl1_MouseUp(object sender, MouseEventArgs e)
{
if (leftFlag)
{
leftFlag = false;//释放鼠标后标注为false;
}
}
private void groupControl1_MouseMove(object sender, MouseEventArgs e)
{
if (leftFlag)
{
Point mouseSet = Control.MousePosition;
mouseSet.Offset(mouseOff.X, mouseOff.Y); //设置移动后的位置
Location = mouseSet;
}
}
private void groupControl1_MouseDown(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Left)
{
mouseOff = new Point(-e.X, -e.Y); //得到变量的值
leftFlag = true; //点击左键按下时标注为true;
}
}
private void groupControl1_MouseDown(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Left)
{
mouseOff = new Point(-e.X, -e.Y); //得到变量的值
leftFlag = true; //点击左键按下时标注为true;
}
}
2.调用windows API
调用前需要添加using System.Runtime.InteropServices;
[csharp] view plain copy
[DllImport("user32.dll")]
public static extern bool ReleaseCapture();
[DllImport("user32.dll")]
public static extern bool SendMessage(IntPtr hwnd, int wMsg, int wParam, int lParam);
private void groupControl1_MouseDown(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Left)
{
ReleaseCapture(); //释放鼠标捕捉
//发送左键点击的消息至该窗体(标题栏)
SendMessage(Handle, 0xA1, 0x02, 0);
}
}
跪求大神指点, vb.net 的图片鼠标事件 怎么把鼠标单击双击和鼠标按下鼠标放开 分辨出来呢?
单击双击和按下松开本身就是重合的操作，分不开的，你想达到什么样的操作目的？
如何在VB.net中用程序控制鼠标移动和点击
调用api
在Visual Baisc.net中的声明：
Declare Sub mouse_event Lib "user32" (ByVal dwFlags As Long, ByVal dx As Long, ByVal dy As Long, ByVal cButtons As Long, ByVal dwExtraInfo As Long)
Public Const MOUSEEVENTF_LEFTDOWN = H2 '模拟鼠标左键按下
Public Const MOUSEEVENTF_LEFTUP = H4 ’模拟鼠标左键释放
Public Const MOUSEEVENTF_MIDDLEDOWN = H20 '模拟鼠标中间键按下
Public Const MOUSEEVENTF_MIDDLEUP = H40 '模拟鼠标中间键释放
Public Const MOUSEEVENTF_RIGHTDOWN = H8 '模拟鼠标右键按下
Public Const MOUSEEVENTF_RIGHTUP = H10 '模拟鼠标右键释放
Public Const MOUSEEVENTF_MOVE = H1 '模拟鼠标指针移动
例：
mouse_event MOUSEEVENTF_LEFTDOWN,10,10,0,0
'在（10，10）模拟鼠标左键按下
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