如何在JavaScript,Scala和ABAP里实现尾递

在JavaScript, Scala和ABAP里实现尾递归(Tail Recursion)，针对这个问题，这篇文章详细介绍了相对应的分析和解答，希望可以帮助更多想解决这个问题的小伙伴找到更简单易行的方法。

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Before we start to research tail recursion, let’s first have a look at the normal recursion.

A simple factorial implementation by recursion:

function factorial(n){
  if(n ===1) {
     return 1;
  }
  return n *factorial(n -1);}

Let N = 5, see how new stack frame is created for each time of recursive call:

如何在JavaScript, Scala和ABAP里实现尾递

We have two stack frames now, one stores the context when n = 5, and the topmost one for current calculation: n = 4

如何在JavaScript, Scala和ABAP里实现尾递

Now since n equals to 1, we stop recursion. The current stack frame ( n = 1 ) will be poped up, the frame under it will be activated and become the topmost frame, with calculated result 1 passed into.

如何在JavaScript, Scala和ABAP里实现尾递

key note for normal recursion: during recursion, every generated stack frame is needed and could not e destroyed until the final result is calculated. The calculation is actually not started until the recursion reaches the end ( the condition n === 1 fulfills ). If N is a big integer, it will lead to huge number of stack frames and finally the “stack overflow” or “out of memory” is inevitable.

tail recursion

Source code below:

function tailFactorial(n, total) {if(n ===1)
    return total;return tailFactorial(n -1, n * total);}function factorial2(n) {
  return tailFactorial(n,1);}

There are two biggest differences compared with normal recursion:

(1) A new internal function tailFactorial is introduced here.

(2) The calculation is actually now spread within every recursive stack frame. Each frame finishes one part of calculation and pass the current result to the next frame. Once the current stack frame finishes its task, it is actually not needed any more. And thus for example the model browser can then do some optimization on those useless stack frames.

Observe the stack frame for tail recursion step by step:

如何在JavaScript, Scala和ABAP里实现尾递

stack popped up:

如何在JavaScript, Scala和ABAP里实现尾递

When N = 20, the tail recursion has a far better performance than the normal recursion:

如何在JavaScript, Scala和ABAP里实现尾递

Update 2016-01-11

Tail recursion implementation via Scala:

如何在JavaScript, Scala和ABAP里实现尾递

The interesting thing is, after the Scala code is compiled into Java Byte code, compiler will eliminate the recursion automatically:

如何在JavaScript, Scala和ABAP里实现尾递

Tail Recursion in ABAP

First this is the normal recursion:

REPORT zrecursion.
START-OF-SELECTION.
  DATA: lv_result TYPE int4.
  PERFORM fac USING 6 CHANGING lv_result.
  WRITE: / lv_result.
FORM fac USING iv_n TYPE int4 CHANGING cv_result TYPE int4.
  DATA: lv_n TYPE i.
  cv_result = lv_n = iv_n.
  lv_n = lv_n - 1.
  IF lv_n > 1.
    PERFORM fac USING lv_n CHANGING cv_result.
  ENDIF.
  IF lv_n = 1.
    cv_result = cv_result * lv_n.
  ELSE.
    cv_result = cv_result * iv_n.
  ENDIF.
ENDFORM.

And here comes tail recursion version:

REPORT ztail.
START-OF-SELECTION.
  DATA: lv_result TYPE int4.
  PERFORM fac USING 5 1 CHANGING lv_result.
  WRITE: / lv_result.
FORM fac USING iv_n TYPE int4 iv_acc TYPE int4 CHANGING cv_result TYPE int4.
  DATA: lv_n          TYPE i,
        lv_accumulate TYPE i.
  IF iv_n < 1.
    cv_result = 1.
  ELSEIF iv_n = 1.
    cv_result = iv_acc * iv_n.
  ELSEIF iv_n > 1.
    lv_n = iv_n - 1.
    lv_accumulate = iv_acc * iv_n.
    PERFORM fac USING lv_n lv_accumulate CHANGING cv_result.
  ENDIF.
ENDFORM.

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如何在JavaScript,Scala和ABAP里实现尾递

tail recursion

Update 2016-01-11

Tail Recursion in ABAP

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